96=-16t2+96t+5

Solution for 96=-16t2+96t+5 equation:

96=-16t^2+96t+5

We move all terms to the left:

96-(-16t^2+96t+5)=0

We get rid of parentheses

16t^2-96t-5+96=0

We add all the numbers together, and all the variables

16t^2-96t+91=0

a = 16; b = -96; c = +91;
Δ = b2-4ac
Δ = -962-4·16·91
Δ = 3392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3392}=\sqrt{64*53}=\sqrt{64}*\sqrt{53}=8\sqrt{53}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-8\sqrt{53}}{2*16}=\frac{96-8\sqrt{53}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+8\sqrt{53}}{2*16}=\frac{96+8\sqrt{53}}{32}
$