8x-3(x+2)=4(x+1)

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Solution for 8x-3(x+2)=4(x+1) equation: 



8x-3(x+2)=4(x+1)

We move all terms to the left:

8x-3(x+2)-(4(x+1))=0

We multiply parentheses

8x-3x-(4(x+1))-6=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

5x-(4x+4)-6=0

We get rid of parentheses

5x-4x-4-6=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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