96=(x+5)(x+1)

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Solution for 96=(x+5)(x+1) equation:



96=(x+5)(x+1)
We move all terms to the left:
96-((x+5)(x+1))=0
We multiply parentheses ..
-((+x^2+x+5x+5))+96=0
We calculate terms in parentheses: -((+x^2+x+5x+5)), so:
(+x^2+x+5x+5)
We get rid of parentheses
x^2+x+5x+5
We add all the numbers together, and all the variables
x^2+6x+5
Back to the equation:
-(x^2+6x+5)
We get rid of parentheses
-x^2-6x-5+96=0
We add all the numbers together, and all the variables
-1x^2-6x+91=0
a = -1; b = -6; c = +91;
Δ = b2-4ac
Δ = -62-4·(-1)·91
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-20}{2*-1}=\frac{-14}{-2} =+7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+20}{2*-1}=\frac{26}{-2} =-13 $

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