5(3x+1)2+6(3x+1)-8=0

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Solution for 5(3x+1)2+6(3x+1)-8=0 equation: 



5(3x+1)2+6(3x+1)-8=0

We multiply parentheses

30x+18x+10+6-8=0

We add all the numbers together, and all the variables

48x+8=0

We move all terms containing x to the left, all other terms to the right

48x=-8

x=-8/48

x=-1/6

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