936=(2x+4)*(x+6)

Solution for 936=(2x+4)*(x+6) equation:

936=(2x+4)(x+6)

We move all terms to the left:

936-((2x+4)(x+6))=0

We multiply parentheses ..

-((+2x^2+12x+4x+24))+936=0


We calculate terms in parentheses: -((+2x^2+12x+4x+24)), so:

(+2x^2+12x+4x+24)

We get rid of parentheses

2x^2+12x+4x+24

We add all the numbers together, and all the variables

2x^2+16x+24

Back to the equation:

-(2x^2+16x+24)


We get rid of parentheses

-2x^2-16x-24+936=0

We add all the numbers together, and all the variables

-2x^2-16x+912=0

a = -2; b = -16; c = +912;
Δ = b2-4ac
Δ = -162-4·(-2)·912
Δ = 7552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7552}=\sqrt{64*118}=\sqrt{64}*\sqrt{118}=8\sqrt{118}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{118}}{2*-2}=\frac{16-8\sqrt{118}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{118}}{2*-2}=\frac{16+8\sqrt{118}}{-4}
$