6(x+3)+3(2x-4)=30

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Solution for 6(x+3)+3(2x-4)=30 equation: 



6(x+3)+3(2x-4)=30

We move all terms to the left:

6(x+3)+3(2x-4)-(30)=0

We multiply parentheses

6x+6x+18-12-30=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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