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90+52=5x^2
We move all terms to the left:
90+52-(5x^2)=0
We add all the numbers together, and all the variables
-5x^2+142=0
a = -5; b = 0; c = +142;
Δ = b2-4ac
Δ = 02-4·(-5)·142
Δ = 2840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2840}=\sqrt{4*710}=\sqrt{4}*\sqrt{710}=2\sqrt{710}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{710}}{2*-5}=\frac{0-2\sqrt{710}}{-10} =-\frac{2\sqrt{710}}{-10} =-\frac{\sqrt{710}}{-5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{710}}{2*-5}=\frac{0+2\sqrt{710}}{-10} =\frac{2\sqrt{710}}{-10} =\frac{\sqrt{710}}{-5} $
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