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x(x+60)=4400
We move all terms to the left:
x(x+60)-(4400)=0
We multiply parentheses
x^2+60x-4400=0
a = 1; b = 60; c = -4400;
Δ = b2-4ac
Δ = 602-4·1·(-4400)
Δ = 21200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{21200}=\sqrt{400*53}=\sqrt{400}*\sqrt{53}=20\sqrt{53}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-20\sqrt{53}}{2*1}=\frac{-60-20\sqrt{53}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+20\sqrt{53}}{2*1}=\frac{-60+20\sqrt{53}}{2} $
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