9/5f=27

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Solution for 9/5f=27 equation: 



9/5f=27

We move all terms to the left:

9/5f-(27)=0



Domain of the equation: 5f!=0

f!=0/5

f!=0

f∈R



We multiply all the terms by the denominator


-27*5f+9=0

Wy multiply elements

-135f+9=0

We move all terms containing f to the left, all other terms to the right

-135f=-9

f=-9/-135

f=1/15

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