(2)/(3)b+4=5

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Solution for (2)/(3)b+4=5 equation: 



(2)/(3)b+4=5

We move all terms to the left:

(2)/(3)b+4-(5)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

2/3b-1=0

We multiply all the terms by the denominator


-1*3b+2=0

Wy multiply elements

-3b+2=0

We move all terms containing b to the left, all other terms to the right

-3b=-2

b=-2/-3

b=2/3

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