If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9/3x+12/3=3x+4
We move all terms to the left:
9/3x+12/3-(3x+4)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
9/3x-(3x+4)+4=0
We get rid of parentheses
9/3x-3x-4+4=0
We multiply all the terms by the denominator
-3x*3x-4*3x+4*3x+9=0
Wy multiply elements
-9x^2-12x+12x+9=0
We add all the numbers together, and all the variables
-9x^2+9=0
a = -9; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-9)·9
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*-9}=\frac{-18}{-18} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*-9}=\frac{18}{-18} =-1 $
| (5x-5)+(3x+3)=5 | | -2(y+2)=2(2-2y) | | Y2+8y+42=0 | | 2(6x+7)=3(4x-5) | | -3(x+4)=x-24 | | -2(x+1)=x-3-2 | | -14.4+-13.4z=-12.5z | | 2x+4=10* | | m=2*(5-1)^2/4 | | -3(x+4)=x-24 | | -(x-3)+2=16 | | 5(-2x-3)=5 | | ?x7=392 | | 2(2b-4)+6=3(2b+10)-10 | | 7(m–2)=4(3m+4) | | 392=x7 | | 2x^4-3x^3-12x^2-7x+6=0 | | 4(9y+2)=2(3y-5) | | -2y+4(1-3y)=-10y-2y-8 | | 3(3h-10)-2(2h+5)=-20 | | 14/3n=-1 | | 5x^2=10x-4 | | ((2^3)^180*2^600*3^2)/(2^2)^567=n | | x=18(90-x) | | (2)/(-x)=(-1/2) | | 3(3x-4)=4(2x-1); | | -42+5x=18 | | 3(3x–4)=4(2x-1); | | 5.6g+6=2.6g+21 | | n5+3=20 | | 4x-25=2x-11 | | 3.5z−2.7z=-6 |