2(2b-4)+6=3(2b+10)-10

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Solution for 2(2b-4)+6=3(2b+10)-10 equation: 



2(2b-4)+6=3(2b+10)-10

We move all terms to the left:

2(2b-4)+6-(3(2b+10)-10)=0

We multiply parentheses

4b-(3(2b+10)-10)-8+6=0



We calculate terms in parentheses: -(3(2b+10)-10), so:

3(2b+10)-10

We multiply parentheses

6b+30-10

We add all the numbers together, and all the variables

6b+20

Back to the equation:

-(6b+20)



We add all the numbers together, and all the variables

4b-(6b+20)-2=0

We get rid of parentheses

4b-6b-20-2=0

We add all the numbers together, and all the variables

-2b-22=0

We move all terms containing b to the left, all other terms to the right

-2b=22

b=22/-2

b=-11

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