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9/2x+18+3x=5.5
We move all terms to the left:
9/2x+18+3x-(5.5)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3x+9/2x+12.5=0
We multiply all the terms by the denominator
3x*2x+(12.5)*2x+9=0
We multiply parentheses
3x*2x+25x+9=0
Wy multiply elements
6x^2+25x+9=0
a = 6; b = 25; c = +9;
Δ = b2-4ac
Δ = 252-4·6·9
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{409}}{2*6}=\frac{-25-\sqrt{409}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{409}}{2*6}=\frac{-25+\sqrt{409}}{12} $
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