9/2-x-10/x-5=0

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Solution for 9/2-x-10/x-5=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

9/2-x-(10/x)-5 = 0

9/2-x-10*x^-1-5 = 0

-1*x^1-10*x^-1-1/2*x^0 = 0

(-1*x^2-1/2*x^1-10*x^0)/(x^1) = 0 // * x^2

x^1*(-1*x^2-1/2*x^1-10*x^0) = 0

x^1

(-1/2)*x-x^2-10 = 0

(-1/2)*x-x^2-10 = 0

DELTA = (-1/2)^2-(-10*(-1)*4)

DELTA = -159/4

DELTA < 0

x in { } 

x belongs to the empty set

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