(5/y)+(4/y)=3

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Solution for (5/y)+(4/y)=3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

5/y+4/y = 3 // - 3

5/y+4/y-3 = 0

9*y^-1 = 3 // : 9

y^-1 = 1/3

-1 < 0

1/(y^1) = 1/3 // * y^1

1 = 1/3*y^1 // : 1/3

3 = y^1

y = 3

y = 3

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