9/2(y+3)=27

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Solution for 9/2(y+3)=27 equation: 



9/2(y+3)=27

We move all terms to the left:

9/2(y+3)-(27)=0



Domain of the equation: 2(y+3)!=0

y∈R



We multiply all the terms by the denominator


-27*2(y+3)+9=0

Wy multiply elements

-54y(y+9=0

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