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2=x(x-1)
We move all terms to the left:
2-(x(x-1))=0
We calculate terms in parentheses: -(x(x-1)), so:We get rid of parentheses
x(x-1)
We multiply parentheses
x^2-1x
Back to the equation:
-(x^2-1x)
-x^2+1x+2=0
We add all the numbers together, and all the variables
-1x^2+x+2=0
a = -1; b = 1; c = +2;
Δ = b2-4ac
Δ = 12-4·(-1)·2
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3}{2*-1}=\frac{-4}{-2} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3}{2*-1}=\frac{2}{-2} =-1 $
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