9/10m-3=-19/20m+2

Solution for 9/10m-3=-19/20m+2 equation:

9/10m-3=-19/20m+2

We move all terms to the left:

9/10m-3-(-19/20m+2)=0


Domain of the equation: 10m!=0

m!=0/10

m!=0

m∈R



Domain of the equation: 20m+2)!=0

m∈R


We get rid of parentheses

9/10m+19/20m-2-3=0

We calculate fractions


180m/200m^2+190m/200m^2-2-3=0

We add all the numbers together, and all the variables

180m/200m^2+190m/200m^2-5=0

We multiply all the terms by the denominator


180m+190m-5*200m^2=0

We add all the numbers together, and all the variables

370m-5*200m^2=0

Wy multiply elements

-1000m^2+370m=0

a = -1000; b = 370; c = 0;
Δ = b2-4ac
Δ = 3702-4·(-1000)·0
Δ = 136900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{136900}=370$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(370)-370}{2*-1000}=\frac{-740}{-2000}
=37/100
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(370)+370}{2*-1000}=\frac{0}{-2000}
=0
$