(3x-6)/6=(x-2)/2

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Solution for (3x-6)/6=(x-2)/2 equation: 



(3x-6)/6=(x-2)/2

We move all terms to the left:

(3x-6)/6-((x-2)/2)=0

We calculate fractions


3x/()+(-((x-2)*6)/()=0



We calculate terms in parentheses: +(-((x-2)*6)/(), so:

-((x-2)*6)/(

We multiply all the terms by the denominator


-((x-2)*6)



We calculate terms in parentheses: -((x-2)*6), so:

(x-2)*6

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

-6x+12

Back to the equation:

+(-6x+12)



We get rid of parentheses

3x/()-6x+12=0

We multiply all the terms by the denominator


3x-6x*()+12*()=0

We add all the numbers together, and all the variables

3x-6x*()=0

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