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9-x=3/5x
We move all terms to the left:
9-x-(3/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-x-(+3/5x)+9=0
We add all the numbers together, and all the variables
-1x-(+3/5x)+9=0
We get rid of parentheses
-1x-3/5x+9=0
We multiply all the terms by the denominator
-1x*5x+9*5x-3=0
Wy multiply elements
-5x^2+45x-3=0
a = -5; b = 45; c = -3;
Δ = b2-4ac
Δ = 452-4·(-5)·(-3)
Δ = 1965
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{1965}}{2*-5}=\frac{-45-\sqrt{1965}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{1965}}{2*-5}=\frac{-45+\sqrt{1965}}{-10} $
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