13(n+2)-6(8n-4)=n

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Solution for 13(n+2)-6(8n-4)=n equation: 



13(n+2)-6(8n-4)=n

We move all terms to the left:

13(n+2)-6(8n-4)-(n)=0

We add all the numbers together, and all the variables

-1n+13(n+2)-6(8n-4)=0

We multiply parentheses

-1n+13n-48n+26+24=0

We add all the numbers together, and all the variables

-36n+50=0

We move all terms containing n to the left, all other terms to the right

-36n=-50

n=-50/-36

n=1+7/18

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