9-6(x+11)=2(x-4)+27

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Solution for 9-6(x+11)=2(x-4)+27 equation: 



9-6(x+11)=2(x-4)+27

We move all terms to the left:

9-6(x+11)-(2(x-4)+27)=0

We multiply parentheses

-6x-(2(x-4)+27)-66+9=0



We calculate terms in parentheses: -(2(x-4)+27), so:

2(x-4)+27

We multiply parentheses

2x-8+27

We add all the numbers together, and all the variables

2x+19

Back to the equation:

-(2x+19)



We add all the numbers together, and all the variables

-6x-(2x+19)-57=0

We get rid of parentheses

-6x-2x-19-57=0

We add all the numbers together, and all the variables

-8x-76=0

We move all terms containing x to the left, all other terms to the right

-8x=76

x=76/-8

x=-9+1/2

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