9-5(x+1)=7-3(x+3)

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Solution for 9-5(x+1)=7-3(x+3) equation: 



9-5(x+1)=7-3(x+3)

We move all terms to the left:

9-5(x+1)-(7-3(x+3))=0

We multiply parentheses

-5x-(7-3(x+3))-5+9=0



We calculate terms in parentheses: -(7-3(x+3)), so:

7-3(x+3)

determiningTheFunctionDomain
-3(x+3)+7

We multiply parentheses

-3x-9+7

We add all the numbers together, and all the variables

-3x-2

Back to the equation:

-(-3x-2)



We add all the numbers together, and all the variables

-5x-(-3x-2)+4=0

We get rid of parentheses

-5x+3x+2+4=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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