(4y+4)-(3+3y)=11

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Solution for (4y+4)-(3+3y)=11 equation: 



(4y+4)-(3+3y)=11

We move all terms to the left:

(4y+4)-(3+3y)-(11)=0

We add all the numbers together, and all the variables

(4y+4)-(3y+3)-11=0

We get rid of parentheses

4y-3y+4-3-11=0

We add all the numbers together, and all the variables

y-10=0

We move all terms containing y to the left, all other terms to the right

y=10

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