9-4(3x+1)=3(6-3x)=9

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Solution for 9-4(3x+1)=3(6-3x)=9 equation: 



9-4(3x+1)=3(6-3x)=9

We move all terms to the left:

9-4(3x+1)-(3(6-3x))=0

We add all the numbers together, and all the variables

-4(3x+1)-(3(-3x+6))+9=0

We multiply parentheses

-12x-(3(-3x+6))-4+9=0



We calculate terms in parentheses: -(3(-3x+6)), so:

3(-3x+6)

We multiply parentheses

-9x+18

Back to the equation:

-(-9x+18)



We add all the numbers together, and all the variables

-12x-(-9x+18)+5=0

We get rid of parentheses

-12x+9x-18+5=0

We add all the numbers together, and all the variables

-3x-13=0

We move all terms containing x to the left, all other terms to the right

-3x=13

x=13/-3

x=-4+1/3

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