8=2(b+-1)

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Solution for 8=2(b+-1) equation: 



8=2(b+-1)

We move all terms to the left:

8-(2(b+-1))=0

We add all the numbers together, and all the variables

-(2(b-1))+8=0



We calculate terms in parentheses: -(2(b-1)), so:

2(b-1)

We multiply parentheses

2b-2

Back to the equation:

-(2b-2)



We get rid of parentheses

-2b+2+8=0

We add all the numbers together, and all the variables

-2b+10=0

We move all terms containing b to the left, all other terms to the right

-2b=-10

b=-10/-2

b=+5

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