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9-3x(x-2)=x-1
We move all terms to the left:
9-3x(x-2)-(x-1)=0
We multiply parentheses
-3x^2+6x-(x-1)+9=0
We get rid of parentheses
-3x^2+6x-x+1+9=0
We add all the numbers together, and all the variables
-3x^2+5x+10=0
a = -3; b = 5; c = +10;
Δ = b2-4ac
Δ = 52-4·(-3)·10
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{145}}{2*-3}=\frac{-5-\sqrt{145}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{145}}{2*-3}=\frac{-5+\sqrt{145}}{-6} $
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