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5(x-4)-(4x-3)=4(2x+2)-4
We move all terms to the left:
5(x-4)-(4x-3)-(4(2x+2)-4)=0
We multiply parentheses
5x-(4x-3)-(4(2x+2)-4)-20=0
We get rid of parentheses
5x-4x-(4(2x+2)-4)+3-20=0
We calculate terms in parentheses: -(4(2x+2)-4), so:We add all the numbers together, and all the variables
4(2x+2)-4
We multiply parentheses
8x+8-4
We add all the numbers together, and all the variables
8x+4
Back to the equation:
-(8x+4)
x-(8x+4)-17=0
We get rid of parentheses
x-8x-4-17=0
We add all the numbers together, and all the variables
-7x-21=0
We move all terms containing x to the left, all other terms to the right
-7x=21
x=21/-7
x=-3
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