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9-2(3x-4)=2(x+4)
We move all terms to the left:
9-2(3x-4)-(2(x+4))=0
We multiply parentheses
-6x-(2(x+4))+8+9=0
We calculate terms in parentheses: -(2(x+4)), so:We add all the numbers together, and all the variables
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
-6x-(2x+8)+17=0
We get rid of parentheses
-6x-2x-8+17=0
We add all the numbers together, and all the variables
-8x+9=0
We move all terms containing x to the left, all other terms to the right
-8x=-9
x=-9/-8
x=1+1/8
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