8y+3-10y=-(2y-3)

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Solution for 8y+3-10y=-(2y-3) equation: 



8y+3-10y=-(2y-3)

We move all terms to the left:

8y+3-10y-(-(2y-3))=0

We add all the numbers together, and all the variables

-2y-(-(2y-3))+3=0



We calculate terms in parentheses: -(-(2y-3)), so:

-(2y-3)

We get rid of parentheses

-2y+3

Back to the equation:

-(-2y+3)



We get rid of parentheses

-2y+2y-3+3=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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