9-(3c+1)=0.5(2c+12)

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Solution for 9-(3c+1)=0.5(2c+12) equation: 



9-(3c+1)=0.5(2c+12)

We move all terms to the left:

9-(3c+1)-(0.5(2c+12))=0

We get rid of parentheses

-3c-(0.5(2c+12))-1+9=0



We calculate terms in parentheses: -(0.5(2c+12)), so:

0.5(2c+12)

We multiply parentheses

c+6

Back to the equation:

-(c+6)



We add all the numbers together, and all the variables

-3c-(c+6)+8=0

We get rid of parentheses

-3c-c-6+8=0

We add all the numbers together, and all the variables

-4c+2=0

We move all terms containing c to the left, all other terms to the right

-4c=-2

c=-2/-4

c=1/2

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