9-(2-54)=6+2y-(5+y)

Solution for 9-(2-54)=6+2y-(5+y) equation:

9-(2-54)=6+2y-(5+y)

We move all terms to the left:

9-(2-54)-(6+2y-(5+y))=0

We add all the numbers together, and all the variables

-(6+2y-(y+5))+9-(-52)=0

We add all the numbers together, and all the variables

-(6+2y-(y+5))+61=0


We calculate terms in parentheses: -(6+2y-(y+5)), so:

6+2y-(y+5)

determiningTheFunctionDomain
2y-(y+5)+6

We get rid of parentheses

2y-y-5+6

We add all the numbers together, and all the variables

y+1

Back to the equation:

-(y+1)


We get rid of parentheses

-y-1+61=0

We add all the numbers together, and all the variables

-1y+60=0

We move all terms containing y to the left, all other terms to the right

-y=-60

y=-60/-1

y=+60