3(x+2)+4x=6(x-2)

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Solution for 3(x+2)+4x=6(x-2) equation: 



3(x+2)+4x=6(x-2)

We move all terms to the left:

3(x+2)+4x-(6(x-2))=0

We add all the numbers together, and all the variables

4x+3(x+2)-(6(x-2))=0

We multiply parentheses

4x+3x-(6(x-2))+6=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

7x-(6x-12)+6=0

We get rid of parentheses

7x-6x+12+6=0

We add all the numbers together, and all the variables

x+18=0

We move all terms containing x to the left, all other terms to the right

x=-18

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