9-(2-3)=6+2y-(5+y)

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Solution for 9-(2-3)=6+2y-(5+y) equation: 



9-(2-3)=6+2y-(5+y)

We move all terms to the left:

9-(2-3)-(6+2y-(5+y))=0

We add all the numbers together, and all the variables

-(6+2y-(y+5))+9-(-1)=0

We add all the numbers together, and all the variables

-(6+2y-(y+5))+10=0



We calculate terms in parentheses: -(6+2y-(y+5)), so:

6+2y-(y+5)

determiningTheFunctionDomain
2y-(y+5)+6

We get rid of parentheses

2y-y-5+6

We add all the numbers together, and all the variables

y+1

Back to the equation:

-(y+1)



We get rid of parentheses

-y-1+10=0

We add all the numbers together, and all the variables

-1y+9=0

We move all terms containing y to the left, all other terms to the right

-y=-9

y=-9/-1

y=+9

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