4(y-7)-6=-7(-3y+4)-8y

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Solution for 4(y-7)-6=-7(-3y+4)-8y equation: 



4(y-7)-6=-7(-3y+4)-8y

We move all terms to the left:

4(y-7)-6-(-7(-3y+4)-8y)=0

We multiply parentheses

4y-(-7(-3y+4)-8y)-28-6=0



We calculate terms in parentheses: -(-7(-3y+4)-8y), so:

-7(-3y+4)-8y

We add all the numbers together, and all the variables

-8y-7(-3y+4)

We multiply parentheses

-8y+21y-28

We add all the numbers together, and all the variables

13y-28

Back to the equation:

-(13y-28)



We add all the numbers together, and all the variables

4y-(13y-28)-34=0

We get rid of parentheses

4y-13y+28-34=0

We add all the numbers together, and all the variables

-9y-6=0

We move all terms containing y to the left, all other terms to the right

-9y=6

y=6/-9

y=-2/3

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