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9-(2+(-3y))=6+2y-(5=y)
We move all terms to the left:
9-(2+(-3y))-(6+2y-(5)=0
We calculate terms in parentheses: -(2+(-3y)), so:We get rid of parentheses
2+(-3y)
determiningTheFunctionDomain (-3y)+2
We get rid of parentheses
-3y+2
Back to the equation:
-(-3y+2)
3y-(6+2y-5+9-2=0
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