x+5(x+1)=19+4x

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Solution for x+5(x+1)=19+4x equation: 



x+5(x+1)=19+4x

We move all terms to the left:

x+5(x+1)-(19+4x)=0

We add all the numbers together, and all the variables

x+5(x+1)-(4x+19)=0

We multiply parentheses

x+5x-(4x+19)+5=0

We get rid of parentheses

x+5x-4x-19+5=0

We add all the numbers together, and all the variables

2x-14=0

We move all terms containing x to the left, all other terms to the right

2x=14

x=14/2

x=7

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