9(y-8)=3(4y+1)=3

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Solution for 9(y-8)=3(4y+1)=3 equation: 



9(y-8)=3(4y+1)=3

We move all terms to the left:

9(y-8)-(3(4y+1))=0

We multiply parentheses

9y-(3(4y+1))-72=0



We calculate terms in parentheses: -(3(4y+1)), so:

3(4y+1)

We multiply parentheses

12y+3

Back to the equation:

-(12y+3)



We get rid of parentheses

9y-12y-3-72=0

We add all the numbers together, and all the variables

-3y-75=0

We move all terms containing y to the left, all other terms to the right

-3y=75

y=75/-3

y=-25

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