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5x-5-x=2(x-4)+7
We move all terms to the left:
5x-5-x-(2(x-4)+7)=0
We add all the numbers together, and all the variables
4x-(2(x-4)+7)-5=0
We calculate terms in parentheses: -(2(x-4)+7), so:We get rid of parentheses
2(x-4)+7
We multiply parentheses
2x-8+7
We add all the numbers together, and all the variables
2x-1
Back to the equation:
-(2x-1)
4x-2x+1-5=0
We add all the numbers together, and all the variables
2x-4=0
We move all terms containing x to the left, all other terms to the right
2x=4
x=4/2
x=2
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