9(y-7)=2(4y+3)-69

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Solution for 9(y-7)=2(4y+3)-69 equation: 



9(y-7)=2(4y+3)-69

We move all terms to the left:

9(y-7)-(2(4y+3)-69)=0

We multiply parentheses

9y-(2(4y+3)-69)-63=0



We calculate terms in parentheses: -(2(4y+3)-69), so:

2(4y+3)-69

We multiply parentheses

8y+6-69

We add all the numbers together, and all the variables

8y-63

Back to the equation:

-(8y-63)



We get rid of parentheses

9y-8y+63-63=0

We add all the numbers together, and all the variables

y=0

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