3a+8-a=4a-2(a-4)

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Solution for 3a+8-a=4a-2(a-4) equation: 



3a+8-a=4a-2(a-4)

We move all terms to the left:

3a+8-a-(4a-2(a-4))=0

We add all the numbers together, and all the variables

2a-(4a-2(a-4))+8=0



We calculate terms in parentheses: -(4a-2(a-4)), so:

4a-2(a-4)

We multiply parentheses

4a-2a+8

We add all the numbers together, and all the variables

2a+8

Back to the equation:

-(2a+8)



We get rid of parentheses

2a-2a-8+8=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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