9(y-4)=-10(y+2(1/3)

Solution for 9(y-4)=-10(y+2(1/3) equation:

9(y-4)=-10(y+2(1/3)

We move all terms to the left:

9(y-4)-(-10(y+2(1/3))=0

We add all the numbers together, and all the variables

9(y-4)-(-10(y+2(+1/3))=0

We multiply parentheses

9y-(-10(y+2(+1/3))-36=0

We multiply all the terms by the denominator


9y*3))-36-(-10(y+2(+1=0

We add all the numbers together, and all the variables

9y*3))-36-(-10(y=0

Wy multiply elements

27y^2=0

a = 27; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·27·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{54}=0$