Y=(2x-4)(3x-6)

Solution for Y=(2x-4)(3x-6) equation:

=(2Y-4)(3Y-6)

We move all terms to the left:

-((2Y-4)(3Y-6))=0

We multiply parentheses ..

-((+6Y^2-12Y-12Y+24))=0


We calculate terms in parentheses: -((+6Y^2-12Y-12Y+24)), so:

(+6Y^2-12Y-12Y+24)

We get rid of parentheses

6Y^2-12Y-12Y+24

We add all the numbers together, and all the variables

6Y^2-24Y+24

Back to the equation:

-(6Y^2-24Y+24)


We get rid of parentheses

-6Y^2+24Y-24=0

a = -6; b = 24; c = -24;
Δ = b2-4ac
Δ = 242-4·(-6)·(-24)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{-24}{-12}=+2$