9(y+8)+y=4(y+3)-2

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Solution for 9(y+8)+y=4(y+3)-2 equation: 



9(y+8)+y=4(y+3)-2

We move all terms to the left:

9(y+8)+y-(4(y+3)-2)=0

We add all the numbers together, and all the variables

y+9(y+8)-(4(y+3)-2)=0

We multiply parentheses

y+9y-(4(y+3)-2)+72=0



We calculate terms in parentheses: -(4(y+3)-2), so:

4(y+3)-2

We multiply parentheses

4y+12-2

We add all the numbers together, and all the variables

4y+10

Back to the equation:

-(4y+10)



We add all the numbers together, and all the variables

10y-(4y+10)+72=0

We get rid of parentheses

10y-4y-10+72=0

We add all the numbers together, and all the variables

6y+62=0

We move all terms containing y to the left, all other terms to the right

6y=-62

y=-62/6

y=-10+1/3

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