2(x-3)+(x-4)=7x-10

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Solution for 2(x-3)+(x-4)=7x-10 equation: 



2(x-3)+(x-4)=7x-10

We move all terms to the left:

2(x-3)+(x-4)-(7x-10)=0

We multiply parentheses

2x+(x-4)-(7x-10)-6=0

We get rid of parentheses

2x+x-7x-4+10-6=0

We add all the numbers together, and all the variables

-4x=0

x=0/-4

x=0

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