9(x-1)/3=6(x-3)/10

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Solution for 9(x-1)/3=6(x-3)/10 equation: 



9(x-1)/3=6(x-3)/10

We move all terms to the left:

9(x-1)/3-(6(x-3)/10)=0

We calculate fractions


9x/()+(-(6(x-3)*3)/()=0



We calculate terms in parentheses: +(-(6(x-3)*3)/(), so:

-(6(x-3)*3)/(

We multiply all the terms by the denominator


-(6(x-3)*3)



We calculate terms in parentheses: -(6(x-3)*3), so:

6(x-3)*3

We multiply parentheses

18x-54

Back to the equation:

-(18x-54)



We get rid of parentheses

-18x+54

Back to the equation:

+(-18x+54)



We get rid of parentheses

9x/()-18x+54=0

We multiply all the terms by the denominator


9x-18x*()+54*()=0

We add all the numbers together, and all the variables

9x-18x*()=0

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