3x-2(x+2)=4(x-3+7)

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Solution for 3x-2(x+2)=4(x-3+7) equation: 



3x-2(x+2)=4(x-3+7)

We move all terms to the left:

3x-2(x+2)-(4(x-3+7))=0

We add all the numbers together, and all the variables

3x-2(x+2)-(4(x+4))=0

We multiply parentheses

3x-2x-(4(x+4))-4=0



We calculate terms in parentheses: -(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

x-(4x+16)-4=0

We get rid of parentheses

x-4x-16-4=0

We add all the numbers together, and all the variables

-3x-20=0

We move all terms containing x to the left, all other terms to the right

-3x=20

x=20/-3

x=-6+2/3

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