9(x+4)=3(x+12)

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Solution for 9(x+4)=3(x+12) equation: 



9(x+4)=3(x+12)

We move all terms to the left:

9(x+4)-(3(x+12))=0

We multiply parentheses

9x-(3(x+12))+36=0



We calculate terms in parentheses: -(3(x+12)), so:

3(x+12)

We multiply parentheses

3x+36

Back to the equation:

-(3x+36)



We get rid of parentheses

9x-3x-36+36=0

We add all the numbers together, and all the variables

6x=0

x=0/6

x=0

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