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(x+6)(x+5)=-4x-26
We move all terms to the left:
(x+6)(x+5)-(-4x-26)=0
We get rid of parentheses
(x+6)(x+5)+4x+26=0
We multiply parentheses ..
(+x^2+5x+6x+30)+4x+26=0
We get rid of parentheses
x^2+5x+6x+4x+30+26=0
We add all the numbers together, and all the variables
x^2+15x+56=0
a = 1; b = 15; c = +56;
Δ = b2-4ac
Δ = 152-4·1·56
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-1}{2*1}=\frac{-16}{2} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+1}{2*1}=\frac{-14}{2} =-7 $
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