9(u-3)=3u+27

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Solution for 9(u-3)=3u+27 equation: 



9(u-3)=3u+27

We move all terms to the left:

9(u-3)-(3u+27)=0

We multiply parentheses

9u-(3u+27)-27=0

We get rid of parentheses

9u-3u-27-27=0

We add all the numbers together, and all the variables

6u-54=0

We move all terms containing u to the left, all other terms to the right

6u=54

u=54/6

u=9

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